Benzene and toluene form nearly ideal solution At $20^{\circ} C,$ the vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at $20^{\circ} C$ for a solution containing 78 g of benzene and 46 g of toluene in torr is

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Solution

The correct option is A 50
According to Raoult's law,
$P_{B} = P_{B}^{\circ} X_{B} P_{B}^{\circ} = 75$
$X_{B} = \frac{\frac{78}{78}}{(\frac{78}{78}) + (\frac{46}{92})} = \frac{1}{1 + 0.5} = \frac{1}{1.5} P_{B} = 75 \times \frac{1}{1.5} = 50 t o r r$

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Q. Benzene and toluene form nearly ideal solutions. At

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Benzene and toluene form nearly ideal solution At 20∘C, the vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 20∘C for a solution containing 78 g of benzene and 46 g of toluene in torr is

The correct option is A 50According to Raoult's law, PB=P∘BXBP∘B=75 XB=7878(7878)+(4692)=11+0.5=11.5PB=75×11.5=50 torr

Benzene and toluene form nearly ideal solution At $20^{\circ} C,$ the vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at $20^{\circ} C$ for a solution containing 78 g of benzene and 46 g of toluene in torr is

The correct option is A 50
According to Raoult's law,
$P_{B} = P_{B}^{\circ} X_{B} P_{B}^{\circ} = 75$
$X_{B} = \frac{\frac{78}{78}}{(\frac{78}{78}) + (\frac{46}{92})} = \frac{1}{1 + 0.5} = \frac{1}{1.5} P_{B} = 75 \times \frac{1}{1.5} = 50 t o r r$