Benzene is a resonance hybrid mainly of two Kekule's structures. Hence :
A
half of the molecules correspond to one structure, and half of the second structure
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B
at low temperatures benzene can be separated into two structures
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C
two structures make equal contribution to resonance hybrid
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D
an individual benzene molecule changes back and forth between two structures
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Solution
The correct option is C two structures make equal contribution to resonance hybrid In Kekule's structure, the carbon atoms in benzene are arranged in a hexagonal ring with each carbon atom is attached to two other carbon atoms.
The ring contains alternate single and double bond.
These double bonds are due to the π electrons present in benzene.
These π electrons can delocalize and form two structures with different position of a double bond.
These are the resonance contributor. Thus, they contribute equally to form a resonance hybrid.