Benzene on reaction with conc. $H N O_{3}$ in presence of conc. $H_{2} S O_{4}$ followed by the treatment of $C l_{2}$ in presence of $F e C l_{3}$ , it gives :

2 - c h l o r o - 1 - n i t r o b e n z e n e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 - c h l o r o - 3 - n i t r o b e n z e n e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 - c h l o r o - 1 - n i t r o b e n z e n e

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

A mixture of

2 - c h l o r o

and

4 - c h l o r o - 1 - n i t r o b e n z e n e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $3 - c h l o r o - 1 - n i t r o b e n z e n e$
3-Chloro-1-nitrobenzene
Nitro substituents have positive charge on the atom bonded to ring. So the like charges repel each other at ortho and para position as compared to meta substitution. So meta position is favored at 3 chloro in the ring.

Suggest Corrections

Similar questions

H N O_{3}

H_{2} S O_{4}

H N O_{3}

H N O_{3}

H_{2} S O_{4}

H N O_{3} / H_{2} S O_{4}

A l C l_{3}

The reaction of $C H_{3} C H = C H_{2}$ with HOCI will yield

Join BYJU'S Learning Program