Benzoic acid on treatment with hydrazoic acid $(N_{3} H)$ in the presence of concentrated sulphuric acid gives :

benzamide

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sodium benzoate

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aniline

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C_{6} H_{5} C O N_{3}

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Solution

The correct option is C aniline
Benzoic acid on treatment with hydrazoic acid ( $N_{3} H$ ) in the presence of concentrated sulphuric acid gives aniline.

This reaction is called Schmidt reaction. It involves an isocyanate intermediate.

Option C is correct.

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