Benzoyl chloride is prepared from benzoic acid by:

C l_{2}, h v

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S O_{2}, C l_{2}

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S O C l_{2}

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C l_{2}, H_{2} O

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Solution

The correct option is C $S O C l_{2}$
Here, $S O C l_{2}$ readily replaces $(- O H)$ group of $(- C O O H)$ by $(- C l)$ forming acid chloride.

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Similar questions

Benzoyl chloride is prepared from benzoic acid by

How do you convert the following

a) benzoyl chloride to benzaldehyde b) methyl benzene to benzoic acid

C_{6} H_{3} C O C l B e n z o y l c h l o r i d e + 2 N H_{3} \to C_{6} H_{5} C O N H_{2} B e n z a m i d e + N H_{4} C l

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