Benzoyl chloride is prepared from benzoic acid by

$C l_{2}, h ν$

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$S O_{2} C l_{2}$

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$S O C l_{2}$

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$C l_{2}, H_{2} O$

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Solution

The correct option is C
$S O C l_{2}$

$C_{6} H_{5} C O O H + S O C l_{2} \to C_{6} H_{5} - C O C l$

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Similar questions

How do you convert the following

a) benzoyl chloride to benzaldehyde b) methyl benzene to benzoic acid

C_{6} H_{5} C O C l

P d / B a S O_{4}

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