Beryllium atom in beryllium fluoride is:

s p^{3}

hybridised

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s p^{2}

hybridised

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s p

hybridised

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Unhybridised

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Solution

The correct option is C $s p$ hybridised
In Beryllium Fluoride, the $B e$ atom has $2$ Bond pairs and no lone pairs. So, the hybridisation is $s p$ .

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s p^{3}, s p^{2}, s p^{2}, s p^{3}, s p^{2}, s p^{2}, s p, a n d s p

s p, s p^{2}

s p^{3}

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