Betaine $C_{5} H_{11} O_{2} N$ , occurs in beet sugar molasses. It is water soluble solid that melts with decomposition at $300^{\circ} C$ . It is unaffected by a base but reacts with hydrochloric acid to form a crystalline product $C_{5} H_{12} O_{2} N C l$ . It can be made from glycine with methyl iodide or treatment of chloroacetic acid with trimethyl amine. Draw structure for betaine which will account for all properties given above.

Open in App

Solution

Betaine $C_{5} H_{11} O_{2} N$ reacts with HCl to form crystalline product.

Suggest Corrections

Similar questions

Q. An unknown substance 'S' reacts vigorously with cold water, air and Hydrochloric acid. It remains unaffected by Sodium hydroxide base. Identify the substance amongst the following options.

Which of the following reactions of glucose can be explained only by its cyclic structure?
(a) Glucose forms pentaacetate
(b) Blucose reacts with hydoxylamine to form an oxime
(c) Pentaacetate of glucose does not reach with hydroxyl amine
(d) Glucose is oxidised by nitric acid to gluconic acid

Q. When steam reacts with a metal like iron at a high temperature it gives A and B. The same metal when reacted with an acid forms A and C. Which of the following is/are not true about the properties of A.

Q. (a) What are metals? Name five metals.
(b) Name a metal which is so soft that it can be cut with a knife.
(c) Name the metal which is the best conductor of heat and electricity.
(d) What happens when a metal reacts with dilute hydrochloric acid? Explain with the help of an example.
(e) Write the equations for the reaction of:
(i) Magnesium with dilute hydrochloric acid
(ii) Aluminium with dilute hydrochloric acid
(iii) Zinc with dilute hydrochloric acid
(iv) Iron with dilute hydrochloric acid
Name the products formed in each case. Also indicate the physical states of all the substances involved.

Q. Give reason for the following:
Though lead is above hydrogen in the activity series, it does not react with dilute hydrochloric acid or dilute sulphuric acid.

Join BYJU'S Learning Program

Betaine C5H11O2N reacts with HCl to form crystalline product.

Betaine $C_{5} H_{11} O_{2} N$ reacts with HCl to form crystalline product.