Between 1 and 31 m arithmetic means are inserted so that the ratio of the 7th and (m−1)th means is 5 : 9. Then the value of m is
14
1, x1, x2.....xm, 31 is an A.P. of (m + 2) terms.
31 = Tm+2 = a + (m + 1)d = 1 + (m + 1)d
∴ d = 30(m+1)
Now x7xm−1 = 59 ∴ T8Tm = a+7da+(m−1)d = 59
Now put for a and d and we get m = 14.