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Question

Between 1 and 31 m arithmetic means are inserted so that the ratio of the 7th and (m1)th means is 5 : 9. Then the value of m is


A

12

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B

13

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C

14

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D

15

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Solution

The correct option is C

14


1, x1, x2.....xm, 31 is an A.P. of (m + 2) terms.

31 = Tm+2 = a + (m + 1)d = 1 + (m + 1)d

∴ d = 30(m+1)

Now x7xm1 = 59T8Tm = a+7da+(m1)d = 59

Now put for a and d and we get m = 14.


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