Between $2^{10}$ and $10^{2}$ , $10^{2}$ is greater.

True

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False

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Solution

The correct option is B
False

$2^{10}$ = $(2^{5})^{2}$ = $(2 \times 2 \times 2 \times 2 \times 2)^{2}$ = 32×32 = 1024

$10^{2}$ = 10×10 = 100

Since 1024 > 100 so, $2^{10}$ is greater than $10^{2}$ .

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Among $2^{10}$ and $10^{2}$ , $10^{2}$ is greater.

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