Question

$B{F}_3$ forms an adduct with $N{H}_3$ because:

• A. nitrogen has high electronegativity
• B. boron has high electronegativity
• C. boron has an empty p-orbital and nitrogen has lone pair of electrons
• D. boron has electro positive nature

Answer 1

Answer: (C)

boron has an empty p-orbital and nitrogen has lone pair of electrons

$B{F}_3$ forms adduct with $N{H}_3$ because of the dative bond formed between $B{F}_3$ and $N{H}_3$.