BF 3 with LiAlH 4 on reduction gives-A- B 2 H 6B- BAlH 4C- BD- LiB

The correct option is A B_2 H_64BF_3 + 3Li AlH_4 → 2B_2 H_6 + 3LiF + 3AlF_3 ...

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Reactivity with Halogens and Hydrogen (Group 2)

BF 3 with LiA...

Question

$B F_{3}$ with $L i A l H_{4}$ on reduction gives:

B_{2} H_{6}

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B A l H_{4}

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B

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L i B

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