Bhanu bought 3 kg 500 gm of jilebi, 2 kg 250 gm of mysorepak and 1 kg 750 gm badhushaw and 750 gm of jamun. What is the total weight of the sweets that Bhanu bought?

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Solution

Add all the amount in kg first
$(3 k g + 2 k g + 1 k g) = 5 k g$
Now the weight given in gm
$(500 g + 250 g + 750 g + 750 g) = 2250 g = 2 k g 250 g m$
So total weight =
$(5 k g + 2 k g 250 g m) = 7 k g 250 g m$

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Bhanu bought 3 kg 500 gm of jilebi, 2 kg 250 gm of mysorepak and 1 kg 750 gm badhushaw and 750 gm of jamun. What is the total weight of the sweets that Bhanu bought?

Add all the amount in kg first(3kg+2kg+1kg)=5kg Now the weight given in gm (500g+250g+750g+750g)=2250g=2kg250gmSo total weight = (5kg+2kg250gm)=7kg250gm

Add all the amount in kg first
$(3 k g + 2 k g + 1 k g) = 5 k g$
Now the weight given in gm
$(500 g + 250 g + 750 g + 750 g) = 2250 g = 2 k g 250 g m$
So total weight =
$(5 k g + 2 k g 250 g m) = 7 k g 250 g m$