Bi-cyclohexane was found to undergo two parallel first order rearrangements- At 730 K- the first order rate constant for the formation of cyclohexane was measured as 1-26- 10-4s-1 and for the formation of methyl cyclopentene the rate constant was 3-8- 10-5 s-1- What was the - distribution of the rearrangement products-

Percentage of cyclohexane= k_1k_1+k_2× 100 =1.26 × 10^ 41.26 × 10^ 4+3.8 × 10^ 5× 100 #160; =77% Percentage of methyl cyclopentane =77% Re ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Entropy for a Reversible Process

Bi-cyclohexan...

Question

Bi-cyclohexane was found to undergo two parallel first order rearrangements. At $730 K$ , the first order rate constant for the formation of cyclohexane was measured as $1.26 \times 10^{- 4} s^{- 1}$ and for the formation of methyl cyclopentene the rate constant was $3.8 \times 10^{- 5} s^{- 1}$ . What was the $%$ distribution of the rearrangement products.

Open in App

Solution

Suggest Corrections

Similar questions

A

A \to B

A \to C

1.26 \times 10^{- 4} s^{- 1}

3.8 \times 10^{- 5} s^{- 1}

B

C

(A)

A

1.52 \times 10^{- 4} {s e c}^{- 1}

(B)

(C)

(B)

11.2

K_{1} = 1.26 \times 10^{- 4} s e c^{- 1}

K_{2} = 3.8 \times 10^{- 5} s e c^{- 1}

0.1 M

H C l

5.40 \times 10^{- 5} s^{- 1}

0.1

M H_{2} S O_{4}

6.20 \times 10^{- 5} s^{- 1}

K_{1} = 1.25 \times 10^{- 4} S^{- 1}

K_{2} = 3.80 \times 10^{- 5} S^{- 1}

B

Join BYJU'S Learning Program