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Question

Bi-cyclohexane was found to undergo two parallel first order rearrangements. At 730 K, the first order rate constant for the formation of cyclohexane was measured as 1.26×104s1 and for the formation of methyl cyclopentene the rate constant was 3.8×105s1. What was the % distribution of the rearrangement products.

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Solution

Percentage of cyclohexane=k1k1+k2×100

=1.26×1041.26×104+3.8×105×100

=77%

Percentage of methyl cyclopentane=77%

Remaining is 23%

So the sum of the percentage distribution is 100.
Ans-100


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