Bill wanted to confirm his observation regarding the physical sizes of occupants of the -House of Rational Numbers- Q- He observed two such occupants - 2-3 - and - 3-5 -Bill told himself - 3-5 - has physically a larger size- Say whether Bill-s inference is True or False-

The correct option is A False 2/3 and 3/5 can also be expressed as 10/15 and 9/15. as 10/15 gt; 9/15 therefore, 2/3 gt; 3/5 ...

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Standard VII

Mathematics

Introduction to Rational Numbers

Bill wanted t...

Question

Bill wanted to confirm his observation regarding the physical sizes of occupants of the “House of Rational Numbers, Q”. He observed two such occupants – " $\frac{2}{3}$ " and " $\frac{3}{5}$ "

Bill told himself – " $\frac{3}{5}$ " has physically a larger size. Say whether Bill’s inference is True or False.

True

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False

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Solution

The correct option is B
False

$\frac{2}{3}$ and $\frac{3}{5}$ can also be expressed as $\frac{10}{15}$ and $\frac{9}{15}$ .
as $\frac{10}{15}$ > $\frac{9}{15}$
therefore, $\frac{2}{3}$ > $\frac{3}{5}$

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Similar questions

Bill took his time to admire the “House of Rational Numbers, Q”. He observed an interesting feature of the occupants on Earth 2.

The physical size of the occupants depends on their numerical value, i.e. if “a” and “b” are two occupants of the house, the sizes of “a” and “b” depend on the numerical values“a” and “b”. If a $>$ b, then “a” would appear larger and if a $<$ b, “a” would appear smaller compared to “b”

Bill noticed TWO occupants of the house which were equal in size. Who could these occupants be? Choose all the correct possible pairs.

Having left the “House of Rational Numbers, Q”, Bill wandered off to a playground where a group of occupants (numbers) of Earth 2 were playing. He observed that a team consisted only of the occupants from one room or a house.

The captain of one such team was " $\frac{2}{3}$ " an occupant of “House of Rational Numbers, Q”. He needs to pick players who are part of his house only. Select all the possible players given in the options below that the captain could pick.

During his initial days of stay in Earth 2, Bill had got his accommodation with “1/5” and “1/2” in “House of Rational Numbers, Q”. Having located these occupants, he wanted to locate other occupants satisfying the following conditions:

1. They lie between 1/5 and 1/2.

2. They have a denominator 10.

Which of the following occupants satisfy these properties?

Bill was curious to find the room into which the previous number went in (which exited the “Hall of Division” when occupants “7” and “8” went in). He came out of the room he was in and was surprised at what he saw!

He noticed that the previous rooms he saw – Room N, Room W and Room I were all inside a huge house whose nameplate read – “House of Rational Numbers, Q”. This house of rational numbers was part of a huge villa – many times larger. Bill couldn’t see the nameplate of this villa.

He realized that the arrangements of the Rooms N, W and I inside “House of Rational Numbers, Q” were in logical accordance with the nature of numbers in Earth 1. What could Bill’s inferences be? Choose ALL the correct inferences Bill should have made.

Bill heard that in “The Hall of Operations”, there was another ancient temple, named “The Reciprocus”.

Legend says that when an occupant, say “a”, of the “House of Rational Numbers, Q” enters the temple, it exits the temple as a different occupant, “b”,belonging to the same house. Bill observed that, these occupants “a” and “b”, when they enter the hall of multiplication, they exit the hall as “1”.

Bill realized that the numerical counterparts of a and b (Earth 1) are ___________ of each other.

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Bill wanted to confirm his observation regarding the physical sizes of occupants of the “House of Rational Numbers, Q”. He observed two such occupants – "23" and "35" Bill told himself – "35" has physically a larger size. Say whether Bill’s inference is True or False.

The correct option is B False 23 and 35 can also be expressed as 1015 and 915. as 1015 > 915 therefore, 23 > 35

The correct option is B
False

$\frac{2}{3}$ and $\frac{3}{5}$ can also be expressed as $\frac{10}{15}$ and $\frac{9}{15}$ .
as $\frac{10}{15}$ > $\frac{9}{15}$
therefore, $\frac{2}{3}$ > $\frac{3}{5}$