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Question

Binary stars of comparable masses rotate under the influence of each others gravity at a distance [8Gω2]1/3, where ω is the angular velocity of each of the system. If difference between the masses of two star is 6 units. Find the ratio of the masses of smaller to bigger star.


1022606_85877a956554440090e6fbf861390098.png

A
4:10
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B
1:7
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C
2:8
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D
3:9
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Solution

The correct option is B 1:7
REF.Image.
m2m1=6u

r=(8Gω2)1/3

a1=(Fnet)m1=Gm1m2r2m1=Gm2r2

as; ω2r1=Gm2r2...(1)

and similarly
ω2r2=Gm1r2...(ii)

dividing (1) and (ii)
r1r2=m2m1
adding (i) and (ii)

ω2(r1+r2)=Gr2(m1+m2)

ω2r3=G(m1+m2)=8G

8G=G(m1+m2) (On putting the value of r from question)

m1+m2=8

m2m1=6u

m1+m2=8u

m1=1u

m2=7u

m1:m2=1:7 Ans
Option (B)

1407809_1022606_ans_ac43a56b50b44705994ab5d7665ff815.png

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