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Bond Order by MOT

Binding energ...

Question

Binding energies $_{1} H^{2},_{2} H^{4},_{26} F e^{56}, a n d_{92} U^{235}$ of nuclei are 2.22MeV, 28.4MeV, 492MeV and 1768 MeV respectively. Which one of the following is more stable?

A

_{1} H^{2}

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B

_{2} H^{4}

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C

_{26} F e^{56}

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D

_{92} U^{235}

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Solution

The correct option is B $_{1} H^{2}$
The element with lowest binding energy per nucleon is more stable. Hence $_{1} H^{2}$ is most stable among the four.

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Similar questions

Q. Binding energies of

_{1} H^{2},_{2} H e^{4},_{26} F e^{56},

_{92} U^{235}

2.22 M e V, 28.4 M e V, 492 M e V

1786 M e V

respectively which one of the following is more stable?

Q. Binding energies of

_{1} H^{2},_{2} H e^{4},_{26} F e^{56}

_{92} U^{235}

2.2 Mev, 28.4 Mev,

492 Mev

1786 MeV

respectively, which one of the following is more stable?

Q. Katen was studying nuclear physics. There, he collected values of binding energies of

_{1} H^{2},_{2} {H e}^{4},_{26} {F e}^{56}

_{92} U^{235}

2.22 M e V, 28.3 M e V, 492 M e V

1786 M e V

respectively. Then, he got a doubt that stability of the nucleus depends on its binding energy, which among the above four is the most stable nucleus?

Q. If the total binding energies of

_{1} H^{2},_{2} H e^{4},_{26} F e^{56}

_{92} U^{235}

2.22, 28.3, 492

1768

MeV respectively, then identify the most stable nucleus out of the following.

Q. If the total binding energies of

_{1}^{2} H,_{2}^{4} H e,_{26}^{56} F e &_{92}^{235} U

2.22, 28.3, 492

1786

MeV respectively, identify the most stable nucleus of the following.

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