Question

Binding energy of deuterium is $2.23MeV$, then its mass defect in a.m.u. is

• A. $-0.0024$
• B. $-0.0012$
• C. $0.0012$
• D. $0.0024$

Answer 1

The correct option is D $0.0024$

Mass defect $\Delta m=\frac{2.23}{931}=0.0024amu$.