MyQuestionIcon

2

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Stoichiometric Calculations

Binding energ...

Question

Binding energy per nucleon for deuteron $_{1} H^{2}$ is 1.1 MeV and that for helium $_{2} H e^{4}$ is 7 MeV respectively. Energy released in MeV when two deutrons fuse to form a helium nucleus $_{2} H e^{4}$ is (Write upto two difgits after the decimal point.)

Open in App

Solution

$E = 4 \times 7 M e V - (1.1 \times 2) \times 2 M e V = 23.6 M e V$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The binding energies per nucleon for deutron

(_{1} H^{2})

(_{2} H e^{4})

1.1

7.0

MeV respectively. Calculate the energy released, when two deutrons fuse to form a helium nucleus

(_{2} H e^{4})

Q. The binding energy per nucleon of deuteron

(_{1} H^{2})

(_{2} H e^{4})

1.1 M e V

7.0 M e V

, respectively. The energy released when two deuterons fuse to form a helium nucleus is

Q. The binding energies per nucleon for deuteron

(_{1} H^{2})

(_{2} H e^{4})

are 1.1 MeV and 7.0 MeV, respectively. Calculate the energy released when two deuterons fuse to form a helium nucleus

(_{2} H e^{4})

Q. The binding energy per nucleon of

_{1} H^{2}

_{2} H e^{4}

1.1 M e V

7 M e V

, respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is :

Q. The binding energies per nucleon of deuteron

(_{1} H^{2})

and helium atom

(_{2} H e^{4})

1.1 M e V

7 M e V

. If two deuteron atoms react to form a single helium atom, then the energy released is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Stoichiometric Calculations

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Stoichiometric Calculations

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon