Black fur in mice (B) is dominant over brown fur (b). short tail (T) are dominant to long tail(t).What fraction of the progency of cross: $B b T t \times B B t t$ will be expected to have black fur with long tail?

\frac{1}{2}

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\frac{1}{16}

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\frac{3}{16}

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\frac{1}{3}

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Solution

The correct option is A $\frac{1}{2}$
So the correct option is A.

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Black fur in mice (B) is dominant over brown fur (b). short tail (T) are dominant to long tail(t).What fraction of the progency of cross: BbTt×BBtt will be expected to have black fur with long tail?

The correct option is A 12So the correct option is A.

Black fur in mice (B) is dominant over brown fur (b). short tail (T) are dominant to long tail(t).What fraction of the progency of cross: $B b T t \times B B t t$ will be expected to have black fur with long tail?

The correct option is A $\frac{1}{2}$
So the correct option is A.