Bleaching action of $S O_{2}$ is due to :

its reducing nature

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its oxidising nature

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its acidic nature

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its both oxidising as well as reducing nature

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Solution

The correct option is B its reducing nature
$S O_{2} + 2 H_{2} O \to H_{2} S O_{4} + 2 H$

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H_{2} O_{2}

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{S O}_{2}

H_{2} O_{2}

N_{2} H_{4}

Which one acts as both oxidising as well as reducing agent?