Bleaching powder ( $C a O {C l}_{2}$ ) has two types of chlorine atoms with oxidation number of $+ 1$ and $- 1$ . It can be represented as :

{C a}^{2 +} (C l O_{2}^{-}) {C l}^{-}

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{C a}^{2 +} (C l O_{3}^{-}) {C l}^{-}

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{C a}^{2 +} (C l O^{+}) {C l}^{-}

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{C a}^{2 +} (C l O^{-}) {C l}^{-}

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Solution

The correct option is C ${C a}^{2 +} (C l O^{-}) {C l}^{-}$
Bleaching powder has two types of Cl atoms with oxidation number of $+ 1$ and $- 1$ , one is directly attached to $C a$ and other to oxygen. Therefore, it can be representated as ${C a}^{2 +} (C l O^{-}) {C l}^{-}$ .
It has been shown in the structure below:

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Similar questions

K^{+}, C l^{-}, S^{2 -}, C a^{2 +}

S^{2 -}, K^{+}, C a^{2 +}, C l^{-}

The correct order of ionic size of the species $K^{+}, C l^{-}, C a^{2 +}$ and $S^{2 -}$ is:

S^{2 -}, N a^{+}, C a^{2 +}, C l^{-}

N a O H

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