Block A has a weight of 300N and block B has a weight of 50N. Determine the distance that A must descend from rest before it obtains a speed of 2.5m/s. Neglect the mass of the cord and pulleys.
A
0.796m
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B
0.079 m
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C
7.9m
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D
0.79 cm
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Solution
The correct option is C 0.796m LetaccelerationofAbea,thentheaccelerationofBis2a.ForB2ndlawofmotionisT−50=5×2aForAis300−2T=30asolvingthesetwoweget,a=4m/s2v2−u2=2as⇒s=v22a=2.528=0.796m