Block $A$ in the figure is released from there when the Extension in the spring is $x 0$ . The maximum downward displacement of the block will be:

M g / 2 K - x_{0}

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M g / 2 K + x_{0}

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2 M g / K - x_{0}

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2 M g / K + x_{0}

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Solution

The correct option is B $M g / 2 K + x_{0}$
If the spring is stretched by x
the block comes down by $\frac{x}{2}$
$M g = k x$
the maximum displacement of the block is $\frac{M g}{2 k} + x_{0}$

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Block A in the figure is released from there when the Extension in the spring is x0. The maximum downward displacement of the block will be:

The correct option is B Mg/2K+x0If the spring is stretched by xthe block comes down by x2Mg=kxthe maximum displacement of the block is Mg2k+x0

Block $A$ in the figure is released from there when the Extension in the spring is $x 0$ . The maximum downward displacement of the block will be:

The correct option is B $M g / 2 K + x_{0}$
If the spring is stretched by x
the block comes down by $\frac{x}{2}$
$M g = k x$
the maximum displacement of the block is $\frac{M g}{2 k} + x_{0}$