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Standard XII

Physics

Average and Instaneous Power

Block A of ma...

Question

Block A of mass 2 kg is placed over a block B of mass 8 kg. The combination is placed on a rough horizontal surface. If g = 10 $m s^{- 2}$ , coefficient of friction between B and floor = 0.5, coefficient of friction between A and B = 0.4 and a horizontal force of 10 N is applied on 8 kg block, then the force of friction between A and B is

10 N

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5 N

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4 N

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none of these

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Solution

The correct option is D none of these
From above

firstly check maximum friction at ground

= $0.5 \times (8 + 2) g$

= $0.5 \times 100$

= $50 N$

Since $50 N > 10 N$ the applied so there is no friction between A and B

hence (D) is correct answer

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The correct option is D none of theseFrom above firstly check maximum friction at ground =0.5×(8+2)g=0.5×100=50NSince 50N>10N the applied so there is no friction between A and Bhence (D) is correct answer

The correct option is D none of these
From above

firstly check maximum friction at ground

= $0.5 \times (8 + 2) g$

= $0.5 \times 100$

= $50 N$

Since $50 N > 10 N$ the applied so there is no friction between A and B

hence (D) is correct answer