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Question

Block A of mass 2m, B and C each of mass m are in equilibrium and at rest shown in the figure. The spring balance, pulley and strings are mass less. Now, a force mg is applied on block C in downward direction. Find the new reading of spring balance. Assume all pulleys to the frictionless.


A
5m2
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B
3m2
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C
2m
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D
m
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Solution

The correct option is B 3m2
2T - 2mg = 2ma
Tmg=ma
2T - 2mg - 2ma
Tmg=ma

A=2mgmg2m=g2

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