1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Block A of mass 35 kg is resting on a frictionless floor. Another block B of mass 7 kg is resting on it as shown in the figure. The coefficient of static friction and kinetic friction are 0.5 and 0.4 respectively. If a horizontal force of 100 N is applied to block B, then the acceleration of the block A will be: (g=10ms−2)

A
0.8ms2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2.4ms2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.4ms2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4.4ms2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A 0.8ms2Static friction friction force between two blocksfs≤μNN=mg=7×10=70Nfs≤μs×70fs≤0.5×70fs≤35Nhere force applied is grater than static friction hence body is in motion, then there is kinetic frictionfk=μk×70fk=0.4×70fk=28Nfor mass 35 kg force applied is only kinetic friction f1=fk=28Nacceleration of mass 35 kg is a=f135=2835=0.8m/s2Option A is corrrect

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program