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Question

Block A of mass 35 kg is resting on a frictionless floor. Another block B of mass 7 kg is resting on it as shown in the figure. The coefficient of static friction and kinetic friction are 0.5 and 0.4 respectively. If a horizontal force of 100 N is applied to block B, then the acceleration of the block A will be: (g=10ms2)

282414_45a0159868bb4ff4af65e3e735d62ea0.png

A
0.8ms2
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B
2.4ms2
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C
0.4ms2
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D
4.4ms2
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Solution

The correct option is A 0.8ms2

Static friction friction force between two blocks
fsμNN=mg=7×10=70Nfsμs×70fs0.5×70fs35N
here force applied is grater than static friction
hence body is in motion, then there is kinetic friction
fk=μk×70fk=0.4×70fk=28N
for mass 35 kg force applied is only kinetic friction
f1=fk=28N
acceleration of mass 35 kg is
a=f135=2835=0.8m/s2

Option A is corrrect


563420_282414_ans_d7f9bbbb2ca945cda49919aa06e8c820.png

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