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Question

Block A of mass m and block B of mass 2m are placed on a fixed triangular wedge by means of massless, inextensible string and a frictionless pulley as shown. The wedge is inclined at 45 to horizontal on both sides. The coefficient of friction between block A and wedge is 2/3 and that between block B and wedge is 1/3. If system of A and B is released from rest then acceleration of A is :

136799_ec6f4e6425614d70ab1a3bcc8770e84c.png

A
zero
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B
1ms1
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C
2ms1
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D
3ms1
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Solution

The correct option is A zero
Total maximum friction force ,ft=fA+fB=μAμmgcos45o+μB2mgcos45o
or ft=mg(23.12+13.2.12)=432mg
The net pulling force , F=2mgsin45omgsin45o=mg2
Since, F<ft . thus the blocks will not move. So acceleration of block A is zero.
174634_136799_ans_5ff2f78d25ec451ebbd3d0182bd627f2.png

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