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Question

Block A of weight 100 kg rests on a block B and is tied with a horizontal string to the wall at C. Block B weights 200 kg . The coefficients of friction between A and B is 0.25 and between B and surface is 1/3. The horizontal force F necessary to move the block B should be (g=10m/s2)
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A
1150 N
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B
1250 N
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C
1300 N
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D
1420 N
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Solution

The correct option is B 1250 N
Required force must be at least equal to friction for offerd by both the contact surfaces.Thai is friction force applied by block B on A and by the ground surface on the block B.
F=μABRA+μBSRB
=0.25×100g+13(100+200)g
=25g+100g=125g
=125×10=1250g

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