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Question

Block A of weight 100 N reset on a frictionless inclined plane of slope angle 4300 as shown in the figure. A flexible cord attached to A passes over a frictionless pulley and is connected to block B of weight W. Find the weight W of which the system is in equilibrium.

941568_d5d20057c62f4161ba10bd3e925a6d18.png

A
25 N
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B
50 N
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C
75 N
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D
100 N
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Solution

The correct option is B 50 N
As the system is in equilibrium,
T=W ........(i)
and T=mgsin300 .......(ii)
From (i) and (ii), we get
W=mgsin300=(100N)×12=50N
1069947_941568_ans_a2e28d356d6b4a03ac0bc200cea2961d.png

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