Block B of mass 100kg rests on a rough surface of friction coefficient μ=13. A rope is tied to block B as shown in figure. The maximum acceleration with which boy A of 25kg can climb on rope without making block move is (g=10ms−2)
A
4g3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
g3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
g2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3g4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Bg3 Tcos37∘=f N+Tsin37∘=mg ∴N=100g−Tsin37∘=100g−3T5
and, Tcos37∘=μN Tcos37∘=μ(100g−3T5)
On solving, T=10003N(μ=13) ∴T−Mg=Mamax 10003−250=25×amax amax=103m/s2