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Question

# Block B of weight 'W' is lying on a table . The coefficient of static friction between the block and table is μ. Assume that the cord between B and the knot is horizontal. The maximum weight of the block A for which the system will be stationary is

A
Wtanθμ
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B
μWtanθ
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C
μW1+tan2θ
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D
μWsinθ
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Solution

## The correct option is D μWtanθLet weight of A is W′. From the free body diagram For equilibrium of the system,Tcosθ=μN=μW .................... (i)Tsinθ=W′ ................... (ii)where, T= tension in the thread lying between knot and the support.On dividing Eq. (ii) by Eq. (i), we getTsinθTcosθ=W′μW⇒tanθ=W′μW⇒W′=μWtanθ

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