Block B rests on a smooth surface. If the coefficient of static friction between A and B is μ=0.4. Determine the acceleration of each block, if weight of lower block is 250N and F=30N.
A
0.85ms−2
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B
1ms−2
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C
1.65ms−2
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D
2ms−2
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Solution
The correct option is A0.85ms−2
Limiting friction between A and B fL=μN=0.4×100=40N
(a) Both the blocks will have a tendency to move together with same acceleration (say a). So, the free body diagram is as shown.
Equations of motion are, 30−f=10×a....(i) f=25×a......(ii)
solving these two equations, we get a=0.857m/s2andf=21.42N
As this force is less than fL, both the blocks will moves together with same acceleration, aA=aB=0.857m/s2