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Question

Block B rests on a smooth surface. The coefficient of static friction between A and B is μ=0.4. When F= 30 N, then the acceleration of the upper block is:
988820_2667b27320e04abc888e8f931b67e249.png

A
3/2ms2
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B
6/7ms2
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C
4/3ms2
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D
3/7ms2
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Solution

The correct option is B 6/7ms2
fmax=μN

fm=(0.4)100

fm=40N

In this case, F=f

( friction is self balancing )

For B+A block,

F=mB×Aa=WA+Bga

30=(100+250)10a

a=3035m/s2

a=67m/s2

1489752_988820_ans_2a754adff5784eef9044882d22c9e88c.png

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