Block is initially at rest, it is pulled by 2t, μs=0.4μk=0.38. Force 2t is gradually increasing, then at t=8 sec:
(→w is weight, →fr =frictional force)
A
→F+→N+→fr=−→w
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B
→F+→N+→fr=→w
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C
→N+→fr+→w=→F
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D
body is accelerated
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Solution
The correct option is A→F+→N+→fr=−→w
fnet=μsN = 0.4 ×4×10= 16 N = Fapplied(at t=8 s) . So, the body will not move. since the forces are in equilibrium , using parallelogram vector addition law, →F+→N+→fr=−→w