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Question

Block M slides down on a frictionless inclined plane as shown in the figure. What is the minimum coefficient of friction so that m does not slide with respect to M?

135455_82e4ceae549e42cd82722e98edcb144f.png

A
4/3
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B
1
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C
3/4
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D
3 /5
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Solution

The correct option is B 3/4
Given both the block are at rest with respect to each other so let us solve the problem in the frame of M which is moving along the incline with g×sin37.
Let the friction be f, then by applying newton's second law along the incline and perpendicular to it we have,
f×sin37+N×cos37=m×g×cos37
f×cos37=N×sin37
Solving them will give,
f=3/4
219560_135455_ans_77aadeeefe7e45edb25c20d4b67f90c8.png

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