Question

Block of mass 3 kg is initially in equilibrium and is hanging by two identical springs A and B as shown in figures. If spring A is cut from lower point at t=0 then, find acceleration of block in $m{s}^{-2}$ at t = 0. (Take $g=10m{s}^{-2}$

• A. 5
• B. 10
• C. 15
• D. 0

Answer 1

The correct option is A

5

Initially

mg= 2K $x_0$----(1)
$\Rightarrow K{x}_0=\frac{mg}{2}$
when one spring is cut

mg - $k{x}_0$ = ma
mg - $\frac{mg}{2}$ = ma (from (1))

⇒ a= $\frac{g}{2}$. This result as can be seen is independent of mass of the block.

$\Rightarrow a=\frac{10}{2}=5m{s}^{-2}$