Block R has mass 3 m and velocity 5 v. Another body S has mass 5 m and velocity 1.5 v. What is the ratio between momentum of R and S?

$\frac{R}{S}$ = $\frac{2}{1}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$\frac{R}{S}$ = $\frac{1}{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{S}{R}$ = $\frac{1}{4}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{R}{S}$ = $\frac{1}{3}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$\frac{R}{S}$ = $\frac{2}{1}$

Momentum = mass x velocity

Momentum of Block R = 3 m x 5 v = 15 mv

Momentum of Block S = 5 x 1.5 v = 7.5 mv

Ratio R:S = 15: 7.5 = 2:1

Suggest Corrections

Similar questions

Q. A particle of mass

1 kg

has velocity

{\to v}_{1} = (2 t)^i

and another particle of mass

2 kg

has velocity

{\to v}_{2} = (t^{2})^j

\begin{matrix} Columm I & Column II (a) Net force on centre of mass at 2 s & (p) \frac{20}{9} unit (b) Velocity of centre of mass at 2 s & (q) \sqrt{68} unit (c) Displacement of centre of mass at 2 s & (r) \frac{\sqrt{80}}{3} unit (s) None \end{matrix}

Q. A body P has mass 2 m and velocity 5 v. Another body Q has mass 8 m and velocity 1.25 v. Find out the ratio of momentum of P and Q.

Q. A body of mass

25 k g

has a momentum of

125 k g m / s

. Calculate the velocity of body

Q. A bullet of mass m having a horizontal velocity of 500 m/s hits a stationary block of mass 6.15 kg. The block breaks into two parts viz. Q (mass of 3 kg) and R (mass of 3.15 kg) with the bullet embedded in R. The parts Q and R travel in the direction of initial velocity of the bullet. If the velocity of Q is 3 m/s and the velocity of R is 5 m/s the massof the bullet m is

A projectile thrown at an angle of $30^{\circ}$ with the horizontal has a range $R_{1}$ . Another projectile thrown, with the same velocity, at an angle $30^{\circ}$ with the vertical, has a range $R_{2}$ . The relation between $R_{1}$ and $R_{2}$ is

Join BYJU'S Learning Program

Block R has mass 3 m and velocity 5 v. Another body S has mass 5 m and velocity 1.5 v. What is the ratio between momentum of R and S?

The correct option is A RS = 21 Momentum = mass x velocity Momentum of Block R = 3 m x 5 v = 15 mv Momentum of Block S = 5 x 1.5 v = 7.5 mv Ratio R:S = 15: 7.5 = 2:1

The correct option is A
$\frac{R}{S}$ = $\frac{2}{1}$

Momentum = mass x velocity

Momentum of Block R = 3 m x 5 v = 15 mv

Momentum of Block S = 5 x 1.5 v = 7.5 mv

Ratio R:S = 15: 7.5 = 2:1