Blocks A and B are resting on a smooth horizontal surface given equal speeds of 2m/s in opposite sense as shown in the figure.
At t=0, the position of blocks are shown, then the co-ordinates of centre of mass at t=3s will be
A
(1,0)
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B
(3,0)
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C
(5,0)
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D
(2.25,0)
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Solution
The correct option is D(2.25,0) At t=0 centre of mass is at mid-point or at (2.25,0)
Velocity of centre of mass is zero.
Hence centre of mass will remain at this position all the time.