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Question

Blocks shown in figure moves with constant velocity 10 m/s towards right. All surfaces in contact are rough. The friction force applied by B on A is:
786242_b17faf2b486846c1843e55488c2b9ca6.png

A
0 N
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B
20 N
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C
10 N
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D
Insufficient data
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Solution

The correct option is A 0 N
Given that both block move with constant velocity.

So, a=0

f=mAa=mA×0=0

f=0

984748_786242_ans_b415bcc8545b4264b067b0bdba45ba81.png

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