wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Blood alcohol (C2H5OH) levels can be determined by the following titration:
16H++2Cr2O27+C2H5OH4Cr3++2CO2+11H2O
The endpoint is reached when the orange (dichromate ion) solution turns green (chromium ion).
How many electrons are transferred when a mole of alcohol is titrated to its endpoint?

A
1.8×1024
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3.6×1024
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
7.2×1024
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
9.6×1024
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 7.2×1024
Before balancing the primary chemical reaction for this alcoholic test is
Cr2O27+C2H5OHCr+3+CO2
Now, on balancing this equation with ion-electron method we see results:-
Oxidation half reaction:-
12e+28H++2CrO274Cr+3+14H2O
Reduction half reaction:- n=12e
3H2O+C2H5OH2CO2+12H++12e
On combining we get given above equation
For 1 mole number of electrons transferred is 12×6.023×1023=7.2×1024
(Avogadro number)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Alkanes - Preparation
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon