Bob of simple pendulum of length $1$ is made of iron. The pendulum is oscillating over a horizontal coil carrying direct current. If the time period of the pendulum $s T$ then

T < 2 π \sqrt{\frac{ℓ}{g}}

and damping is smaller than in air alone

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T = 2 π \sqrt{\frac{ℓ}{g}}

and damping is larger than in air alone

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T > 1 π \sqrt{\frac{ℓ}{g}}

and damping is smaller than in air alone

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T < 2 π \sqrt{\frac{ℓ}{g}}

and damping is larger than in air alone

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Solution

The correct option is B $T = 2 π \sqrt{\frac{ℓ}{g}}$ and damping is larger than in air alone
$\begin{matrix} DC current does not incluce a magnetic field. ∴ iron ball will not be attracted towards the coil ∴ There will be no change in time period T = 2 π \sqrt{l / g} \end{matrix}$

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Bob of simple pendulum of length 1 is made of iron. The pendulum is oscillating over a horizontal coil carrying direct current. If the time period of the pendulum s T then

The correct option is B T=2π√ℓg and damping is larger than in air alone DC current does not incluce a magnetic field. ∴ iron ball will not be attracted towards the coil ∴ There will be no change in time period T=2π√l/g

Bob of simple pendulum of length $1$ is made of iron. The pendulum is oscillating over a horizontal coil carrying direct current. If the time period of the pendulum $s T$ then

The correct option is B $T = 2 π \sqrt{\frac{ℓ}{g}}$ and damping is larger than in air alone
$\begin{matrix} DC current does not incluce a magnetic field. ∴ iron ball will not be attracted towards the coil ∴ There will be no change in time period T = 2 π \sqrt{l / g} \end{matrix}$