Bodies A and B have thermal emissivities of 0.01 and 0.81 respectively. The outer surface areas of the two bodies are same. The two bodies emit total radiant power at the same rate. Find the temperature of B if the temperature of A is 5802K.
A
1634K
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B
1734K
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C
1934K
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D
None of these
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Solution
The correct option is C1934K Applying the Stefan Boltzmann law, P=eAσAT4A=eBσAT4B TB=(eAeB)1/4TA=(0.010.81)1/4(5802) TB=58023=1934K