Body is projected vertically with velocity $10$ m/s on reaching the ground, change in its velocity is(upwards direction is taken as positive)

20

m/s

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- 20

m/s

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z e r o

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n o n e

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Solution

The correct option is B $- 20$ m/s
Initial velocity, $V_{i} = 10 m / s$

On reaching ground, it will take same kinetic energy so the speed will be $10 m / s$ and the velocity will be,

$V_{f} = - 10 m / s$

Negative sign indicates that the direction get inverted.

Change in velocity will be,

$V_{f} - V_{i} = - 10 - 10 = - 20 m / s$

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Body is projected vertically with velocity 10 m/s on reaching the ground, change in its velocity is(upwards direction is taken as positive)

The correct option is B −20 m/sInitial velocity, Vi=10m/sOn reaching ground, it will take same kinetic energy so the speed will be 10m/s and the velocity will be,Vf=−10m/sNegative sign indicates that the direction get inverted.Change in velocity will be,Vf−Vi=−10−10=−20m/s

Body is projected vertically with velocity $10$ m/s on reaching the ground, change in its velocity is(upwards direction is taken as positive)