Question

body thrown up along a frictionless inclined plane of angle of inclination 30∘ covers a distance of 40 m along the plane. If the body id projected with the same speed at an angle of 30∘ with the ground, it will have a range of
(Take g=10 ms−2) please explain it clearly😣😥😥

Answer 1

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Or


Let u be the initial speed with which the body is thrown along the inclined plane. As shown in the figure , the effective deceleration is given by
a=gsinθ=gsin30∘=g2=5ms−2

Now, from the third equation of motion,
v2=u2−2as
⇒0=u2−2×5×40
⇒u=20m/s
A projectile projected at angle θ=30∘ with this speed will have a range of
R=u2sin2θg=20×20×sin60∘10=20√3m
Hence the correct choice is (c).