Bohr Magneton value in S.I. Units is:

9.273 \times 10^{- 24} e r g T^{- 1}

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9.273 \times 10^{- 24} J T^{- 1}

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9.273 \times 10^{- 17} J T^{- 1}

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9.273 \times 10^{- 10} c a l T^{- 1}

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Solution

The correct option is A $9.273 \times 10^{- 24} J T^{- 1}$
1 Bohr Magneton = $9.273 \times 10^{- 24} J T^{- 1}$

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Similar questions

Find the correct statement.

i) Magnetic moment $M n^{2 +}$ ion is $\sqrt{35}$

ii) $T i^{4 +}$ is exhibit purple color

iii) 1 Bohr Magneton= $9.273 \times 10^{- 24}$ Tesla $^{- 1}$

iv) Secondary valency of transition metal ion is equal to its co-ordination number

Match the following .

Set -I Set -II

A) Ferromagnetism 1) $9.273 \times 10^{- 24} J . t e s l a^{- 1}$

B) Paramagnetism 2) $F e, C o, N i$

C) Diamagnetism 3) $C r^{2 +}, F e^{3 +}, M n^{2 +}$

D) Bohr Magneton 4) $Z n^{+ 2}, C u^{+}, S c^{+ 3}$

The correct order of matching is (express in the order A, B, C and D)

10^{5} : 1

0.53 \times 10^{- 8} c m .

⎡ ⎣ ⎛ ⎝ 1 + \frac{1}{10 + \frac{1}{10}} ⎞ ⎠ \times ⎛ ⎝ 1 + \frac{1}{10 + \frac{1}{10}} ⎞ ⎠ - ⎛ ⎝ 1 - \frac{1}{10 + \frac{1}{10}} ⎞ ⎠ \times ⎛ ⎝ 1 - \frac{1}{10 + \frac{1}{10}} ⎞ ⎠ ⎤ ⎦

\div ⎡ ⎣ ⎛ ⎝ 1 + \frac{1}{10 + \frac{1}{10}} ⎞ ⎠ + ⎛ ⎝ 1 - \frac{1}{10 + \frac{1}{10}} ⎞ ⎠ ⎤ ⎦

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