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Question

Boiling point of benzene is 353.23K. When 1.8g of non-volatile solute is dissolved in 90g of benzene. Then boiling point raised to 354.11K. Given K0 (benzene) = 2.53Kkgmol1. Then molecular mass of non-volatile substance is :-

A
58gmol1
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B
120gmol1
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C
116gmol1
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D
60gmol1
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Solution

The correct option is A 58gmol1
ΔTb=364.11353.23
=0.88K
Kb=2.53Kkgmol1
ΔTb=Kb×W2×1000m2×W1
m2=2.53×1.8×10000.88×90
=57.5g
So mass of non volatile solute is =57.5 or 58 gram.

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