The boiling point of benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in 90 g benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. $(K_{b} f o r b e n z e n e i s 2.53 K k g m o l^{- 1})$

10 g

of a non-electrolyte solute

(M = 60 g/mol)

is added to

250 g

of water. The boiling point of the solution is (

K_{b}

for water is

0.52 {K kg mol}^{- 1}

and boiling point of water

= 373.15 K

)
[0.77 Mark]

Q. The molality of an aqueous dilute solution containing non-volatile solute is

0.1 m

. What is the boiling temperature (in

^{\circ} C

) of solution? (Boiling point elevation constant,

K_{b} = 0.52 k g m o l^{- 1} K

; boiling temperature of water

= 100^{\circ} C

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Boiling point of chloroform is 61∘C. After addition of 5.0 g of a non-volatile solute to 20 g chloroform boils at 64.63∘C. If Kb=3.63 K kg mol−1, what is the molecular weight of the solute?

Boiling point of chloroform is $61^{\circ} C .$ After addition of 5.0 g of a non-volatile solute to 20 g chloroform boils at ${64.63}^{\circ} C .$ If $K_{b} = 3.63 {K kg mol}^{- 1},$ what is the molecular weight of the solute?